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Results
0! 17 5.8%
1! 8 2.7%
0 191 65.6%
pi 3 1.0%
ln(i) 17 5.8%
1 8 2.7%
Huh? 47 16.2%

 Survey posted 2005-05-16 19:04 by Jon. Contribute ideas to surveys by sending a mail to survey@ticalc.org.

Re: e^(pi*i) + 1 =
Jonathan Katz
(Web Page)

Survey idea by me.

Reply to this comment    16 May 2005, 19:05 GMT

Re: Re: e^(pi*i) + 1 =
no_one_2000_
(Web Page)

Duh! This one's too easy. :-D Good idea, though.

As a side note, I'm surprised people voted for 0!, 1!, and 1. They're all the same thing and therefore cannot be a possible answer. Eliminating those and the "Huh?" option gives you a 1/3 chance of getting it right.

Reply to this comment    18 May 2005, 21:30 GMT

Re: Re: Re: e^(pi*i) + 1 =
no_one_2000_
(Web Page)

And another reason why nobody should miss this is because the problem is directly answered on Google. Type e^(pi*i)+1 in if you don't believe me (or click the link). :)

Reply to this comment    18 May 2005, 21:34 GMT

Re: Re: Re: Re: e^(pi*i) + 1 =
jesse frey

that would be cheating. can't you just type it into your calculator as well?

Reply to this comment    19 May 2005, 00:03 GMT

Re: Re: Re: Re: Re: e^(pi*i) + 1 =
no_one_2000_
(Web Page)

That depends on the capacity of your calculator. A TI-82 couldn't do it, for instance.

Reply to this comment    20 May 2005, 21:45 GMT

Re: Re: Re: Re: e^(pi*i) + 1 =
Reuven Kawesch

Good call. That's what I did before answering. Kind of a useless waste of time, though.

Reply to this comment    22 May 2005, 14:28 GMT

Re: Re: Re: Re: Re: e^(pi*i) + 1 =
matt zelda

same here but i didnt realize that the 0!wasnt the same as the as the 0 untill it was too late

Reply to this comment    24 May 2005, 15:50 GMT

Re: Re: e^(pi*i) + 1 =
'Liam Bell

i like it

Reply to this comment    22 May 2005, 22:24 GMT

Re: e^(pi*i) + 1 =
anthony C

This equation is often called the "Famous Five" equation, as it uses 5 of the most famous numbers: e, Pi, i, 1 and 0.

Reply to this comment    16 May 2005, 19:14 GMT

Re: Re: e^(pi*i) + 1 =
KermMartian
(Web Page)

Just for the record, 1!=0!=1

Reply to this comment    16 May 2005, 19:51 GMT

Re: Re: Re: e^(pi*i) + 1 =
Jonathan Katz
(Web Page)

Thanks for spoiling the fun! :(

Reply to this comment    16 May 2005, 21:25 GMT

Re: Re: Re: e^(pi*i) + 1 =
Rob van Wijk

I was this close to answering "0!", luckily I saw the exclamation point just in time. But indeed, neither "0!", "1!" nor "1" can be the correct answer, because then there wouldn't be a unique correct answer.
By the way, there are so many answers with a zero or one in it, chances are it's one of those. (When answering a multiple choice question and you can pick from "cat", "dog", "fish" and "pinguin" you already know it's not "pinguin", it's just to far away from the other answers.) So anybody who knows what the exclamation point means and makes an educated guess will end up with the correct answer. (This paragraph did not make any sense whatsoever, did it. :( )

Reply to this comment    17 May 2005, 02:55 GMT

Re: Re: Re: Re: e^(pi*i) + 1 =
Chris Williams

Sure, it makes perfect sense. You said that if two or more answers are the same, then the correct answer is not any of them.

I don't know how to summarise the rest of the paragraph, but it more or less makes sense.

Reply to this comment    17 May 2005, 06:22 GMT

Re: Re: Re: Re: e^(pi*i) + 1 =
Me13579

Plus, there is no such thing as a "pinguin" (penguins, however do exist :-D)

Reply to this comment    18 May 2005, 00:09 GMT

Re: Re: Re: Re: Re: e^(pi*i) + 1 =
Rob van Wijk

Oops, that's the dutch way to spell it. :S My bad, sorry.

Reply to this comment    18 May 2005, 00:57 GMT

Re: Re: Re: Re: e^(pi*i) + 1 =
Zeroko
(Web Page)

My English teacher showed me some test from some other teacher or standards body (I do not remember the details), & on one question it had 2 duplicate answers & an answer which was completely blank (which happened to be the correct one), & I have taken tests on which there were 2 choices that were both correct (& thankfully, accepted as such).

Reply to this comment    18 May 2005, 01:49 GMT

Re: Re: Re: Re: e^(pi*i) + 1 =
db810
(Web Page)

"Name an animal that starts with the letter 'p'.
a) cat
b) dog
c) fish
d) pinguin"
????

Reply to this comment    24 May 2005, 22:51 GMT

Re: Re: Re: Re: e^(pi*i) + 1 =
koolone0

made perfect since penguin has nothing to do with the other animals so its most likely not the answer

Reply to this comment    13 November 2005, 21:51 GMT

Re: Re: Re: e^(pi*i) + 1 =
Lewk Of Serthic
(Web Page)

No kidding.

Reply to this comment    19 May 2005, 04:35 GMT

Re: Re: Re: e^(pi*i) + 1 =
quidnunct

How could that happen? 0*0=0, but 1*1=1? Could I get an explanation?

Reply to this comment    24 May 2005, 00:14 GMT

Re: Re: Re: Re: e^(pi*i) + 1 =
Zaren

well here we go
1! is one 1 so 1
which equals 1 1=1
and well 0! some math people got together and said 0! is 1 and now it is.
ta da thats magnificent

Reply to this comment    24 May 2005, 05:14 GMT

Re: Re: Re: Re: Re: e^(pi*i) + 1 =
db810
(Web Page)

Whenever you do a factorial you include "1" but not "0".
If you included "0" then x!=0 would be true for all x. Mathematitions decided to do the same thing with 0! Start with "1" and don't multiply it by anything. Guess what? You're product is "1"

Reply to this comment    24 May 2005, 22:56 GMT

Re: Re: Re: Re: Re: e^(pi*i) + 1 =
koolone0

either way u put it nothing will always turn into something since everything is constantly changing

Reply to this comment    13 November 2005, 21:54 GMT

Re: Re: e^(pi*i) + 1 =
Timmc
(Web Page)

ti83plus(à) = i ?
Else var(i) = undefined

Reply to this comment    17 May 2005, 09:19 GMT

Re: Re: e^(pi*i) + 1 =
redsoxfan

It's Euler's identity, right? It has been called the most remarkable formula in mathematics.

Reply to this comment    17 May 2005, 12:31 GMT

Re: Re: Re: e^(pi*i) + 1 =
anthony C
(Web Page)

Yes. There is a lot on Google about it, incl. this great article from Wikipedia (check link).

Reply to this comment    18 May 2005, 01:43 GMT

Re: Re: Re: Re: e^(pi*i) + 1 =
redsoxfan

Yeah, I'm doing a project on pi right now and I came across it. It's pretty amazing.

Reply to this comment    18 May 2005, 15:20 GMT

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