Re: Calculus Problem...

To: CALC-TI@LISTS.PPP.TI.COM
Subject: Re: Calculus Problem...
From: GARY WARDALL <gwardall@LAKEFIELD.NET>
Date: Sat, 9 Jan 1999 00:12:12 -0600
Reply-To: GARY WARDALL <gwardall@LAKEFIELD.NET>

Try y^2=x^2+c*x, (Thanks to my TI-92+).
It does check.

Good Luck
G. Wardall



>Okay, this time I have even stumped my math teacher for 3 days with this
>Calculus problem.  I don't know how in the world to work this one:
>
>Solve the differential:
>
>dy/dx = (x^2 + y^2)/(2xy)
>
>My math teacher thinks some trick is being used since you will notice the
>2xy in the denominator.  Said to try something like:
>
>dy/dx = (x^2 + 2xy + y^2 - 2xy)/(2xy)
>dy/dx = ((x + y)^2 - 2xy)/(2xy)
>
>However, that still doesn't get rid of the y in the numerator.  Am I
>missing something?
>
>Thanks for any help that you may provide!
>
>
>                 Thomas J. Hruska -- thruska@tir.com
>Shining Light Productions -- "Meeting the needs of fellow programmers"
>         http://www.geocities.com/SiliconValley/Heights/8504
>                    http://click-on.to/shinelight