Re: Calculation of powers (TI-86)
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Re: Calculation of powers (TI-86)
Okay, so I gave the 5th grade definition. I don not know how TI does
roots, but they most likely inputed one of the meathods we all learned
also in 5th grade to do it on paper. If the root method does not refer
to the exponent method, you can do the following (Basic algebra 2
here, folks): 5^.2= The square root of 2. Therefore, here is what I
would use:
2^2/5
(2*2)/(Fifth root of 2)
This, by the way, is the same way we (humans) do them, as I said, but
with the root part. Geez.
On Wed, 29 Oct 1997 08:02:58 -0800, Scott Guth <saguth@EMAIL.MSN.COM>
wrote:
>Is it possible that the question was referring to exponents in general,
>including fractional exponents?????
>
>If so, then the answer is not so simple. Computing 5^(7.2) is not as easy
>as multiplying 5 by itself 7.2 times! But, 5^(7.2)=(5^7)*(5^.2). 5^7 is
>easy. 5^.2 is probably computed using curve fitting techniques from
>numerical analysis.
>
>Scott
>
>
>-----Original Message-----
>From: Matt Maurano <mtm@MAURANO.COM>
>To: CALC-TI@LISTS.PPP.TI.COM <CALC-TI@LISTS.PPP.TI.COM>
>Date: Wednesday, October 29, 1997 5:26 AM
>Subject: Re: Calculation of powers (TI-86)
>
>
>>You mean exponents? Which, by the way, are a rewritten form of
>>logarithms.
>>
>>Probably the same way we do: 2^5=2*2*2*2*2
>>
>>If you want to know how to do it, you can either use the log button of
>>the ^ button.
>>
>>On Tue, 28 Oct 1997 14:38:19 -0500, Sander van der Harst
>><defaultuser@DOMAIN.COM> wrote:
>>
>>>Hi all!
>>>How exactly does a TI-86 calculate powers? I think it has something to
>>>do with logarithms.
>>>
>>>Thanks,
>>>Kevin DeGraaf
>>
References: