[A83] Re: xor (hl)

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[A83] Re: xor (hl)


ld hl,var1
ld a,4
xor (hl)

Var1: .db 5

(This code XORs 4 with 5.)




>From: "TypeR unknown" <typerfuture@hotmail.com>
>Reply-To: assembly-83@lists.ticalc.org
>To: assembly-83@lists.ticalc.org
>Subject: [A83] Re: xor (hl)
>Date: Mon, 15 Oct 2001 18:35:35 +0200
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>Yes, but the part what I meant was that hl can contain 2 Bytes, so my real
>question is how does a xor 2 bytes ??? (only L?, h with a and l with a??)
>
>
>
>
> >From: Peter-Martijn Kuipers <hyper@hysoft-automation.com>
> >Reply-To: assembly-83@lists.ticalc.org
> >To: assembly-83@lists.ticalc.org
> >Subject: [A83] Re: xor (hl)
> >Date: Wed, 10 Oct 2001 19:59:26 +0200 (CEST)
> >
> >
> >Yep, it does.
> >
> >Suppose a contains %00111010,
> >
> >hl contains $6523 and the byte at $6523 is %10010111
> >
> >then this would happen
> >
> >a:     %00111010
> >(hl):  %10010111    XOR
> >-----------------------
> >new a: %10101101
> >
> >
> >
> > >
> > > i suppose it xor's the byte at adress hl...
> > >
> > > >
> > > > I'm a bit confused, xor uses the a register, right?
> > > > Then if you do xor (hl), does it then xor h with a, and l with a???
> > > >
> > >
> > >
> > >
> >
> >
> >
>
>
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