Re: A83: Re: Square root of 0, OT


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Re: A83: Re: Square root of 0, OT




ok enuff about deviding by 0 and it square root, what would the square root of
Iota be, lodgicaly it should be imposible becouse Iota = the smalest amount
posible( sqr. root of Iota = ERROR)   what my calc says is .7071067812+.70...
??????? 


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