[TIB] Re: TI-83 Basic stumper


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[TIB] Re: TI-83 Basic stumper



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If x is the number you want to convert to a string, use this:=0D
=0D
{0,1}->L1 =0D
{x,x}->L2 =0D
LinReg(ax+b) L1,L2,Y0=0D
Equ>String Y0,Str0=0D
sub(Str0,4,length(Str0)-3) -> Str0=0D
=0D
-------Original Message-------=0D
=0D
From: ti-basic@lists.ticalc.org=0D
Date: Sunday, August 18, 2002 2:00:38 PM=0D
To: ti-basic@lists.ticalc.org=0D
Subject: [TIB] TI-83 Basic stumper=0D
=0D
=0D
Thanks for responding to my first post,=0D
even though it wasn't very informative=0D
or questioning.=0D
=0D
Here's a question I have been struggling=0D
with on the TI-83:=0D
Is there a way in Basic to convert an=0D
integer number to its string representation=0D
in a string variable? For example, in=0D
my current project, "Rogue", I have piles=0D
of gold pieces which the player can pick=0D
up as in the following snippet:=0D
=0D
If (player wants to pick up gold)=0D
randInt(10,100->G {number of gold pieces}=0D
Disp "YOU PICK UP THE",G,"GOLD PIECES."=0D
=0D
But that displays as=0D
=0D
YOU PICK UP THE=0D
85=0D
GOLD PIECES.=0D
=0D
and what I want is more like=0D
=0D
YOU PICK UP THE=0D
85 GOLD PIECES.=0D
=0D
which could be accomplished easily=0D
if I could get the value of G into=0D
Str1, for example:=0D
=0D
Disp "YOU PICK UP THE",Str1+" GOLD PIECES."=0D
=0D
=0D
To forestall for-dummies answers: *YES*, I=0D
know you can use a While loop like this:=0D
=0D
randint(10,100->G=0D
"->Str1=0D
While G=0D
sub("0123456789",10fPart(.1G)+1,1)+Str1->Str1=0D
iPart(.1G->G=0D
End=0D
=0D
but I'm looking for a speedy and less involved=0D
method, something like=0D
=0D
randint(10,100->Y1:Eqn>String(Y1,Str1=0D
=0D
which of course doesn't work, but it would be=0D
nice if it did. (Handling 0 and negative numbers=0D
isn't required, BTW.)=0D
=0D
Thanks!=0D
=0D
-Arthur=0D
ajo at andrew dot cmu dot edu=0D
=0D
=0D
=0D
=2E


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