[A83] Re: simplifying boolean functions (non-programming)
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[A83] Re: simplifying boolean functions (non-programming)
It is indeed must easier when you do it with a Karnough diagram ;)
Here's another question, Is it possible to calculate the 'lay-out' of a
Karnough diagram. I already know how an 2, 3 and 4 variable karnough diagram
looks like but don't know how an 5 variable karnough diagram looks like,
despite trying a couple of times...
I even made an ASM program which makes a truthtable on your calculator!!!
(Perhaps not great news, but keep in mind that I have only started ASM
programming last summer (including stupid things like loops) , and made this
program all by myself :) )
thanks
>From: Peter-Martijn Kuipers <hyper@hysoft-automation.com>
>Reply-To: assembly-83@lists.ticalc.org
>To: assembly-83@lists.ticalc.org
>Subject: [A83] Re: simplifying boolean functions (non-programming)
>Date: Wed, 12 Sep 2001 21:16:14 +0200 (CEST)
>
>
> > Can somebody help me with my homework, it's about boolean logic and
>stuff
> > and there is this question about simplyfying boolean functions
>
>Ahh, a challenge...
>
>(I've just got this stuff too...)
>
> > The function which must be simplified is, for example, like this,
> > _ _ _ _ _
> > abc + a.b.c.de + a.b + d
> _ _
> abc + de + a.b + d
> _ _
> abc + a.b + de + d
> _ _
> a.b + abc + d(e + 1)
> _ _
> a.b + abc + d
>
>Let's check it with a Karnough diagram....
>
>...with me, it turns out fine...
>
>Check it yourself...
>
>
> > Easy ?? Wait a second !!! There is one catch (well 2 actually:))
> > 1- You may not use a truthtable
> > 2- You may not use a Karnough diagram
>Ehm, that's not exactly right,
>it means:
>
>You may not do it JUST by usinga Karnough diagram or truthtable,
>but you must show the algebraic route...
>
>No one's gonna complain if you used one of them to find the answer, and
>then worked to the answer algebraically...
>
>Like:
>
>a + ab +ac +abc.
> it boils down to:
>a
>
>;-)
>
>--Peter-Martijn
>
>
> >
> >
> > Thus you have to use rules like a+a=a and that sort of rules. It's all
>new
> > to me, and I'm having quite a bit of problems with it.
> > I'd be very very greatfull if somebody can explain this to me simply !!!
> >
> >
> >
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