> 1. (pencol) & (penrow), Which is X and which is Y? Column...so x. Row......so y. > 2. Doing this... > ld hl, X*256+Y ;Is the 'h' loaded with X, and 'l' loaded with Y? > ld (pencol), hl ;But now 'l' is at (pencol)? LSB or something? Nah, to move X over to h you must multiply it by 100h right? 100h = 256d. H would go into pencol, and l to penrow...wait, I think you'd do: ld (penrow),hl HTH, James.