Re: TI-M: Yet another integral question...
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Re: TI-M: Yet another integral question...
In a message dated 10/3/00 4:43:46 AM Mountain Daylight Time,
JasonScho@aol.com writes:
> fnInt(y, x) = fnInt(y * dx/dt, t)
> = fnInt(-25 * (cos(t) + (t - 2) * sin(t) - 1) * (cos(t) +
(t -
>
> 2) * sin(t)), t)
>
> I'm sure you can finish it from here.
That just doesn't make sense to me...if I was trying to find the integral of
y(t) dx, that would be fine, but I'm trying to find (err...approximate) the
integral of f(t) dt where f(t) = y( x^-1(t) ) and x^-1(t) is the inverse of
the x(t). These two integrals just don't seem the same to me...am I missing
something?
JayEll