TI-M: Re: I think you're a weenie!!!


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TI-M: Re: I think you're a weenie!!!




umm..  dont you start out with different values to begin with?  (1/3)x^3 !=
(2/3)x^3...  and those different values invalidates the rest of it....


----- Original Message -----
From: "Brandon" <brandon@ez-see.com>
To: "TI-Math" <ti-math@lists.ticalc.org>
Sent: Wednesday, May 17, 2000 8:12 PM
Subject: TI-M: I think you're a weenie!!!


>
> So HA!!!  I know I'm spreading false math!!!  That's why I do it.  Besides
> there is a legal (hopfully!) way to do it.  Here's the derivitive type
proof
> I told you about.  It's in TI-89 syntax with comments on the logic behind
> each step.
>
> (1/3)x^3+x^2+C=(2/3)x^3+x^2+C
> take the derivitve
> x^2+2x=2x^2+2X
> divide by x
> x+2=2x+2
> cancel the 2's
> x=2x
> divide by x again
> 1=2
>
> There you go.  It's all legal (like I said before:  hopefully!!!) and it's
> NOT false math.
>
> Mark Hazard
>
>


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