Re: TIB: Random Number Generation Different From The One Before


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Re: TIB: Random Number Generation Different From The One Before




In a message dated 2/25/99 6:31:48 PM Central Standard Time, Parasyte@jps.net
writes:

> >:seq(A,A,1,24\->\L ; initial list
>  >:for(A,1,50) ; number of times to shuffle
>  >:ipart (24rand)+1\->\B
>  >:ipart (24rand)+1\->\C
>  
>  When will anyone realize that it's not ipart, but int that gets the integer
>  part of a number.
>  ipart gets the IMAGINARY part. I don't think rand makes imaginary numbers.
>  I've had to correct a few basic games that made this same mistake.

If you do want a random integer (on the 86) why not use randint?  The syntax
is randint(lower bound,upper bound) and it returns an integer between lower
and upper inclusive.  So you type randint(1,24)->C.
PJC