Re: ti-syntax...


[Prev][Next][Index][Thread]

Re: ti-syntax...



One way:
 
Y1=(-3<x)(x<3)(x^3 - 12x + 1)
 
If -3<x, the test operation returns 1 (if not, it returns 0). This way, when the value for x is out of range, the value for y is 0. It's not ideal, but works.
 
You could also set the window...
----- Original Message -----
From: Arthur Labenek
To: CALC-TI@LISTS.PPP.TI.COM
Sent: Saturday, January 20, 2001 8:26 PM
Subject: ti-syntax...

I was wondering how one could set up the restriction in the calc? for it to work correctly ?
 
x^3 - 12x + 1, (-3<x<3)
 
would you write it like this ????????? (below)
 
x^3 - 12x + 1,x,x>-3,x<3  (give input error)?
 
 
-any help would be appreciated
 
thanks.


Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com.

****************************************************************** * To UNSUBSCRIBE, send an email TO: listserv@lists.ppp.ti.com * with a message (not the subject) that reads SIGNOFF CALC-TI * * Archives at http://peach.ease.lsoft.com/archives/calc-ti.html ******************************************************************
Follow-Ups: References: