Re: graphing inverse trig functions


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Re: graphing inverse trig functions



I think that y=arccsc x would be written as y=1/(sin^-1 x). arcsec is
the same ony cosine not sine. That's what I think. DrInv does not draw
inverse functions, it simply inverts the x and y coordinates. My
thinking is sin^-1 x is the inverse of sin x, so 1/(sin^-1 x) is the
inverse of 1/(sin x), and csc x=1/(sin x).

-Joseph

 Have A
  :-)
Nice Day


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