Re: int(1/x^2,x,-1,1)
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Re: int(1/x^2,x,-1,1)
For Maple for Windows:
int(1/x^2,x=-1..1) yields infinity
>
>>A few more thoughts on this thread:
>>_____________________
>>Synopsis:
>>
>>The '85 responds to fnInt(1/x^2,x,-1,1) (after a yawning gap of time)
>>with "ERROR 02 DIV BY ZERO."
>>
>>Derive XM for DOS gives INT(1/x^2,x,-1,1) = -2
>>
>>and from Michael Keyton's report, the TI-92 has
>>INT(1/x^2,x,-1,1) = infinity.
>>
>>It seems the '92's answer is the best guess of all!
>>_______________________________________________________
>>So here's another test:
>>The '85 responses to both fnInt(1/x,x,0,1) and fnInt(1/x,x,-1,1) are
>>"ERROR 33 TOL NOT MET" (unless tol is cranked to about 1.9) and
>>"ERROR 02 DIV BY ZERO," respectively.
>>
>>Derive XM responds to INT(1/x,x,0,1) with infinity,
>>while INT(1/x,x,-1,1) gives -i*pi, which looks like an
>>application of Cauchy's residue theorem?!
>>
>>What does the '92 do?
>>________________________________________________________
>>
>>Geoff Hagopian,
>>Palm Desert, CA
>>
>>
>>
>>Digest:
>>.... I don't have the '92, but I'm a Deriver from way back. One of
>>.... the curious bugs in Derive is that, if you integrate 1/x^2 from
>>.... -1 to 1, it give you -2.
>>... <The '92> gives infinity.
>>... What version of Derive are you using?
>>.. I have Derive XM 3.05
>>. David Stoutmeyer really works hard to purge incorrect solutions
>>. in Derive. <snip...>
>>
>
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