Re: Solving with trig functions


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Re: Solving with trig functions



@n54 is an arbitrary integer.  You can put any integer in for @n54 and the
equation will work out...


At 03:56 11/18/96 GMT, dhoover@iquest.net wrote:
>Whenever I type something like solve(sin(x)=1/2,x), I get a wierd answer
>like x=30*(12*@n54+5) or x=30*(12*@n54+1).  What does this mean? I've
>looked all over the manual, but I couldn't find anything. What is this
>@n54?  How is it used, and what do I do with it?
>
>
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