[A83] Re: xor (hl)

To: assembly-83@lists.ticalc.org
Subject: [A83] Re: xor (hl)
From: "TypeR unknown" <typerfuture@hotmail.com>
Date: Mon, 15 Oct 2001 18:35:35 +0200
Reply-To: assembly-83@lists.ticalc.org


Yes, but the part what I meant was that hl can contain 2 Bytes, so my real 
question is how does a xor 2 bytes ??? (only L?, h with a and l with a??)




>From: Peter-Martijn Kuipers <hyper@hysoft-automation.com>
>Reply-To: assembly-83@lists.ticalc.org
>To: assembly-83@lists.ticalc.org
>Subject: [A83] Re: xor (hl)
>Date: Wed, 10 Oct 2001 19:59:26 +0200 (CEST)
>
>
>Yep, it does.
>
>Suppose a contains %00111010,
>
>hl contains $6523 and the byte at $6523 is %10010111
>
>then this would happen
>
>a:     %00111010
>(hl):  %10010111    XOR
>-----------------------
>new a: %10101101
>
>
>
> >
> > i suppose it xor's the byte at adress hl...
> >
> > >
> > > I'm a bit confused, xor uses the a register, right?
> > > Then if you do xor (hl), does it then xor h with a, and l with a???
> > >
> >
> >
> >
>
>
>


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