[A83] Re: Faster Multiplication
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[A83] Re: Faster Multiplication
Of course that would be awful if you did that by hand. However, if you had
read his actual description of the algorith, he just reads all the values
from a predefined table of squares.
In a message dated 5/31/2001 3:43:00 PM Eastern Daylight Time,
Mike3465@aol.com writes:
>
> The only problem that i see with that, is it requires doing power...which
> sort of defeats the whole purpose...
> (3+8)^2-(3-8)^2 == (3+8)(3+8) - (3-8)(3-8)
> There are 2 multiplication that would be required, which rises another
> point,
> if you have to divide by 4, that is even slower then multiplication can be
>
----
Jonah Cohen
<ComAsYuAre@aol.com>
http://jonah.ticalc.org