# Re: A83: Re: Square root of 0, OT

```
Division: The quota is the number which, when multiplied with the denominator,
yields the numerator.
Thus 8/4=2 since 2 * 4 = 8.
8/0 = undefined, since nothing times 0 would actually yield 8.
0/0 = undefined, since _anything_ times 0 would yield 0, so the answer could
be anything.

Principal square root: The positive number that, when multiplied by itself,
yields the number inside the root sign.
Thus sqrt(16) = 4, since 4*4=16 and (-4)*(-4)=16, but only use the positive
number.
sqrt(-1) = i, since i*i=-1 (per definition) and (-i)*(-i)=-1, but only use the
positive number.
sqrt(0) = 0, since 0*0=0. This is the _only_ number that gives 0 when squared.

So I really can't see what's the problem?

Linus

On 05-Sep-98, Scott Dial (Revenant) wrote:

>But,

>A * B = C, then C / A = B

>0 * 0 = 0, then 0 / 0 = 0

>That doesn't work... That is the basis of how they relate to each other

>>
>> Im assuming that the calculator decided to use the wrong properties of
math.
>>                                               __
>> since 0*0=0, then wouldnt the \/ 0  be zero too
>>
>> because the square root of a number is equal to a number, which when
>> multiplied by itself equals the original number inside the square root.
>>
>>
>> jerky@ebicom.net
>> IRC nick: Geori
>> ICQ: 1214597
>>
>> -----Original Message-----
>> From: Scott Dial (Revenant) <homosapian@geocities.com>
>> To: ASM83 <assembly-83@lists.ticalc.org>
>> Date: Friday, September 04, 1998 10:41 PM
>> Subject: A83: Square root of 0, OT
>>
>> >
>> >This is extremely off topic but I figured somebody could tell me here.
>> >The square root of 0 according to my handy-dandy TI-83 is 0. But, here
>> >is where I am lost. Wouldn't the below equation rule 0 as non-real?
>> >
>> >   ___        2
>> >  / 2   --   X
>> >\/ X    --  ---
>> >             X
>> >
>> >If X was zero make this impossible? And if not then how can you prove
>> >the square root of 0 is 0.
>> >
>> >BTW, forgive my ignorance if this something that isn't that complicated.
>> >
>> >-Revenant
>> >

>--
>                     .-"""-.
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```

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