Re: A83: Tutorials...


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Re: A83: Tutorials...




That is the right way.

>  don't you pay too much attention to those 1s now? First you say that
>  only 3 digits can be the rightmost digit. Then when you've calculated the
>  number of possible combinations, you divide that number by two. But by then
>  you've already reduced the number of possible combinations once! I'd say 4
>  digits can be in the units place (3, 1, 5 and 1), then calculate
5*4*3*2*1*
> 4
>  = 480. _This_ number should be halved -> 240 possible combinations.
>  
>  Am I completely wrong?
>  
>  Linus


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