I'm close to 0%. I have many little programs lying around on my HDD, but they are usually experiments that help my real developments.

I didn't account for those type of programs when I voted. I voted based on the percentage of the programs that I carry around on my calc, not testing programs I've made for vti.

Even if I don't count routine tests, I used to have lots of BASIC programs for educational purposes. Nowadays I don't really have any use for my calculator.

Aren't "0%" and "I Don't Upload" the same thing practically? It should be "I don't Program"

"I don't program" and "I don't upload" are complete ly different things. But yeah it should have been: 0.0001-20%

Oh well, not a big deal.

What if someone made 10000 programs but only uploaded 1? It needs to be something like the (0-20] that Matt Marshel put above or maybe 1/(infinity) to 20.

no...1/infinity = 0...it should be like: 1/(infinity-1) hehe...j/k

how about this: lim x->0 1/x

yeah, i know... I messed up, should be lim x->infinity 1/x

... 1/(infinity) is NOT 0. 1/(infinity) is undefined. The LIMIT of 1/x as x approaches infinity is zero; however, 1/(infinity) is NOT 0!

Yeah, I noticed that now, after all you smart calculus people screamed at me (just watch what I do to your precious little dx that got me points off on every single quiz). I always forget notation stuff. But then how bout this limit?

limit as x->1- of (-(X^2)+2X-1)*(X-1)^(-1)

But I forgot if - means from the left or right, if not then sorry.
And don't cheat and use the 89 :)

Zero, just as I suspected.
lim (x->1-) (-(X^2)+2X-1)*(X-1)^(-1) = lim (x->1-) -1*(x-1)(x-1)/(x-1) = lim (x->1-) -(x-1) = -(1-1) = -0 = 0

The TI-89 agrees!

By the way, it's zero from either direction; I believe that x->1- indicates that x approaches 1 from the negative side. I might be wrong.

Well, if 1- is approching from the less than side, with numbers like .999999, then it will technically always be slightly greater. For example:
(-(.9999^2)+2*.9999-1)*(.9999-1)^(-1) = about .0001
while
(-(1.0001^2)+2*1.0001-1)*(1.0001-1)^(-1) = about -.0001
and you can't upload a negative percent of files. Unless you use voodoo magic math, like e^(pi*i)+1=0, which is just so freaky.
(i=radical(-1))

You obviously haven't had calculus yet. There's something called a 'limit' that means that you aren't using exact values. Because the value of f(x) gets closer and closer to zero (from either the positive or negative side) as x decreases towards 1, the limit of f(x) as x approaches 1 is zero.

I am in calculus, but maybe my limits are a little rusty. Some people don't remember EVERYTHING from the first semester and precalc. But I still think that the limit from the negative side has ever decreasing negative numbers. Like lim x->0- 1/x=-infinity, and lim x->0+ 1/x=+infinity.

Then I guess you can assume the first option is 0<x<20, and that zero is the "don't upload" category.

"(2b)||!(2b) -- that is the question" --no_one

ummm...you mean:
(2*b)||!(2*b); that == theQuestion;

How about

TheQuestion = (2*b)||!(2*b);

ahh forgot to add the parenthesis to it so it can return 1 o 0 and store it to TheQuestion
TheQuestion = ((2*b)||!(2*b));

Those would not be necessary, because || has a higher precedence than =.

Oh, and an optimization (assuming TheQuestion is defined as bool, as it should be), since (x || !x) == true:
TheQuestion = true;

But, if TheQuestion is not defined as bool, then that statement is invalid anyway!

-MrM

aaah...the joys of java...
it's a shame the collegeboard changed the compsci language to Java from C++, and it especially sucks for the people who took C++ last year in compsci 1 and now have to learn java all over again in compsci 2...
then again i hear the basic layout is almost the same...is that true?

curse the System.out.println();!!!

I have never uploaded any of my programs, so I hit the "0%-20%" category and clicked "Vote!" and as the page was loading, I then realized my mistake...

I made a mistake. I meant to click 0-20 and it also was when the page was loading did I notice my mistake. I make a whole bunch of program and only my coolest make it on. You can click on my magnifying glass next to my name up at the top of this post.

I suppose it could be different if you upload other people's programs. Then there would be a difference between uploading 0% of your own programs (but any number of others' programs) and not uploading at all.

Factoring in only complete programs, I'm about 50-60% ... but I realize that only after I voted 80-100%.

But that will decrease, as I now have an hp49g+ and will program for it, instead.

-MrM

This is TI, not HP! ;)