[TI-M] Re: Derivative on 83+


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[TI-M] Re: Derivative on 83+



I had assumed he wanted the symbolic version of the equation, but if you
merely want a graph use nDeriv(y1(x),x,x)) as y2(x).

-------Original Message-------

From: ti-math@lists.ticalc.org
Date: Wednesday, September 04, 2002 8:27:54 PM
To: ti-math@lists.ticalc.org
Subject: [TI-M] Re: Derivative on 83+


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<-----Original Message----->
> 
>From: Jonas Jacobsson
>Sent: 9/4/2002 7:47:18 AM
>To: ti-math@lists.ticalc.org
>Subject: [TI-M] Re: Derivative on 83+
>

>
>Ah, yes, Tangent() did the job I was searching for, but it's just a
draw
>function, so it is not possible to trace or use later in any other way.
>
>/jonas
=====
For a polynomial, put the function in a Y1. Go to lists and set up
enough
points to do a regression one less order than the function (e.g., if
your poly
is a cubic, you need three points). Set up L1 as, say, 0, 1, 2.
set up L2 as derivatives of Y1 at 0, 1, 2.

Now, do a quadratic regression, Go to Y2 and install the equation (var,
(5)stats,
Eq, (7)equation. This is the derivative curve in symbolic.


KrazyKyngeKorny






.



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