[TI-M] Re: complexes, ti-89 & 92+, polar and cSolve
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[TI-M] Re: complexes, ti-89 & 92+, polar and cSolve
Carlos:
Seems like the Pi and i constants are being given
a higher precedence than the 2 and 9 (which is
what you probably already know):
e^(Pi * i) + 1 = 0
e^(Pi * i) = -1
e^(Pi * i * 2 / 9 ) != -1 ^ ( 2 / 9 )
Maybe an intermediate step like storing Pi * i * 2 / 9
in a variable [ALPHA]W and then computing e^W would
help.
-- Paul
_________________________________________________________________________
Paul Fitzmeyer
ZOE Medical, Incorporated
460 Boston Street
Topsfield, MA 01983
Phone: (978) 887-1407
Fax: (978) 887-1406
email: paulfitz@zoemedical.com
----- Original Message -----
From: "Carlos Becker" <cjb@softhome.net>
To: <ti-math@lists.ticalc.org>
Sent: Wednesday, March 06, 2002 1:08 PM
Subject: [TI-M] complexes, ti-89 & 92+, polar and cSolve
>
> Hi guys again :)
> I have some problems with cSolve and complex numbers.
> Suppose I have my calc with mode in radian and complex polar form.
Alright,
> now, I do
>
> (being e= euler's constant, and i the imaginary unit)
> e^( i * 2 * Pi / 9) and ENTER -> (-1)^(2/9) appears.. what's that??
>
> then, i want ( e^(i * 2 * Pi/9) ) ^3 -> sin and cos and tg-1 stuff.. but
> can be put back in simplified polar form by doing a tcollect command :)
>
> but. the real problem comes when cSolve(z_^3 - 1/ (sqrt(3)-i)^4 = 0,
> z_) and there are three solutions, which is correct, but the way they're
> displayed is totally annoying to the ones i found by doing it by hand.
>
> Does someone know how to convert those expressions to more simplified
ones?
>
>
> Thank you.
>
>
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