Re: TI-M: Re: Integral of x^x
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Re: TI-M: Re: Integral of x^x
I don't know. But it is my understanding that integral of x in e^(ln x) is
.5x^2. But it still seems that the integral of x in e^(x ln x) is still
e^(x ln x) or integral of x^x
If there is a error here I don't understand it.
----- Original Message -----
From: <JasonScho@aol.com>
To: <ti-math@lists.ticalc.org>
Sent: Sunday, May 28, 2000 1:16 PM
Subject: Re: TI-M: Re: Integral of x^x
>
> In a message dated 5/28/00 9:24:03 PM W. Europe Daylight Time,
> peschippnick@earthlink.net writes:
>
> > integral of a power number mostly x^n, would become x^(n+1)/n, Yes? So
the
> > integral of x^x is x^x .
> > Sinse the first part becomes x^(x+1) and x/x is the same as x^(1-1) So
> > x^(x+1-1) becomes x^x. Yes? So I don't really understand the question?
It
> > can also be written e^(x ln x). The integral of e^n is e^n.
> >
>
> integral of x^n = x^(n+1)/n holds only for constant values of n. The
> integral of e^x is e^x, but the same is not true for e^u.
>
> Tell me, what is the integral of e^(ln x), using your logic? What about
the
> integral of x? And why aren't they the same???
>
> ::terminating condesension mode in 5...4...3...::
>
>
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