Re: TI-M: I think you're a weenie!!!


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Re: TI-M: I think you're a weenie!!!




> (1/3)x^3+x^2+C=(2/3)x^3+x^2+C
> take the derivitve
> x^2+2x=2x^2+2X
> divide by x
> x+2=2x+2
> cancel the 2's
> x=2x

hmmm if x=2x than x MUST be 0!
so then you divide by zero which gives you 
infinity=infinity


> divide by x again
> 1=2
> 
> There you go.  It's all legal (like I said before: 
> hopefully!!!) and it's
> NOT false math.
> 
> Mark Hazard
> 
> 
> 


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