TI-M: I think you're a weenie!!!
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TI-M: I think you're a weenie!!!
So HA!!! I know I'm spreading false math!!! That's why I do it. Besides
there is a legal (hopfully!) way to do it. Here's the derivitive type proof
I told you about. It's in TI-89 syntax with comments on the logic behind
each step.
(1/3)x^3+x^2+C=(2/3)x^3+x^2+C
take the derivitve
x^2+2x=2x^2+2X
divide by x
x+2=2x+2
cancel the 2's
x=2x
divide by x again
1=2
There you go. It's all legal (like I said before: hopefully!!!) and it's
NOT false math.
Mark Hazard
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