Re: TI-M: TI-89 root question
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Re: TI-M: TI-89 root question
I didn't see any problem on the TI-86. You have to put, say, 27^3 with the
superscripted -1 right after it, but if you don't want to use the
superscripted number for some reason, you have to do this: 27^(3^-1)
----Original Message Follows----
From: "Scott Noveck" <noveck@pluto.njcc.com>
Reply-To: ti-math@lists.ticalc.org
To: <ti-math@lists.ticalc.org>
Subject: Re: TI-M: TI-89 root question
Date: Wed, 7 Jun 2000 23:49:37 -0400
> a^(1/n) =
> a^(n^(-1)) = a^n^(-1) because ^ is highest prescedence and right
> associative...(at least in standard arithmetic parsers, but I believe the
> TI-89 follows this convention too)
Don't use that last form (a^n^-1) on the calcs. There's a supposedly a bug
in most ROM versions of most z80 calcs where the precedence of powers to
powers is not evaluated correctly, and that may be taken as (a^n)^-1 rather
than a^(n^-1).
I'm not sure exactly which calcs this affects, but I remember HP listing the
HP49G's correct evaluation of this as a "feature" in which they claimed that
the HP48 line and all ti graphing calcs except the 89, 92(+), and I believe
86 (one of the z80 calcs) all suffer from this incorrect evaluation. I've
got easy access to a friends' 82/83/83+/85/86 calcs in school, so maybe I'll
test it out tomorrow and post the results here.
-Scott
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