TIB: Re: Re: 89/92 @n (the any integer)
[Prev][Next][Index][Thread]
TIB: Re: Re: 89/92 @n (the any integer)
On the 89, "|" is it's own key. It is located to the left of "7" and right
below the "=" key.
-Miles Raymond EML: m_rayman@bigfoot.com
ICQ: 13217756 IRC: Killer2 AIM: kilier2
http://www.bigfoot.com/~m_rayman
----- Original Message -----
From: "The Garth Johnson" <gbjohnson@yahoo.com>
To: <ti-basic@lists.ticalc.org>
Sent: Wednesday, January 05, 2000 11:21 PM
Subject: TIB: Re: 89/92 @n (the any integer)
> that is a problem i have had quite often.. here is how i found a way
around
> it:
> use the | ("with") thing. it is 2nd K on the 92/92+. not sure what it is
on
> the 89
> (6*@n1 + 2)*b | @n1=1 would result in 8b
> (6*@n1 + 2)*b | @n1=0 would result in 2b
>
> what you said makes sense, the question would be does what i just said
make
> any sense...
> g
>
> ----- Original Message -----
> From: "Noah R Deneau" <noahd@juno.com>
> To: <ti-basic@lists.ticalc.org>
> Sent: Wednesday, January 05, 2000 11:01 PM
> Subject: TIB: 89/92 @n (the any integer)
>
> > On certain solves the calc gives back expressions with @n1, or
> > @n(somenumber)
> > Does anyone know how to substitute something like the number 1 in for
the
> > any integer, i.e. get it out of the general solutions form?
> > For instance, change the expression (6*@n1 + 2)*b to something more
> > legible like 8b, or 14b
> >
> > Does that make sense?
> > -Noah
References: