TIB: Re: 89/92 @n (the any integer)


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TIB: Re: 89/92 @n (the any integer)




that is a problem i have had quite often.. here is how i found a way around
it:
use the | ("with") thing. it is 2nd K on the 92/92+.  not sure what it is on
the 89
(6*@n1 + 2)*b | @n1=1 would result in 8b
(6*@n1 + 2)*b | @n1=0 would result in 2b

what you said makes sense, the question would be does what i just said make
any sense...
g
----- Original Message -----
From: "Noah R Deneau" <noahd@juno.com>
To: <ti-basic@lists.ticalc.org>
Sent: Wednesday, January 05, 2000 11:01 PM
Subject: TIB: 89/92 @n (the any integer)


>
> On certain solves the calc gives back expressions with @n1, or
> @n(somenumber)
> Does anyone know how to substitute something like the number 1 in for the
> any integer, i.e. get it out of the general solutions form?
> For instance, change the expression (6*@n1 + 2)*b  to something more
> legible like 8b, or 14b
>
> Does that make sense?
> -Noah
>
>
>


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