Re: TIB: [Fwd: Graphing circles, elipses, etc on 82]


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Re: TIB: [Fwd: Graphing circles, elipses, etc on 82]




A better way of graphing it would be:

Y1={1,-1}solved equasion

For example in your two equasions:
 9x^2+y^2-2y=80 for Y1
 x^2+y^2-10y=0  for Y2
Their respective graphs would be:
 Y1={1,-1}3sqrt(9-x^2)+1
 Y2={1,-1}sqrt(25-x^2)+5

-Miles Raymond      EML: m_rayman@bigfoot.com
ICQ: 13217756       IRC: Killer2        AIM: KilIer2 (kilier2)
http://www.bigfoot.com/~m_rayman/

----- Original Message -----
From: <MathWiz314@aol.com>
To: <ti-basic@lists.ticalc.org>
Sent: Saturday, May 29, 1999 4:08 PM
Subject: Re: TIB: [Fwd: Graphing circles, elipses, etc on 82]


> Solve each of the equations for y on paper.  You should get a square root
> with a plus/minus.
>
> In function mode,
>
> Enter the positive version into y1 and the negative version into y2.
>
> Graph the equations.  It will graph the top piece, then the bottom piece.



References: