Re: TIB: Trig. program. displays answers in radical and pi form!


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Re: TIB: Trig. program. displays answers in radical and pi form!




That would be a nice program to code, but i already went through that unit
it Math A/Trig.  And unlike you, i actually memorized the unit circle for
the test!  =)  Actually we had to because we had like six quizzes over it.
My math teacher was a little obsessed with us learning it.  

I'm also in the middle of writing a triangle solving program.  Shut up!  I
know there are a ton of them out there, but i decided to write one myself.
Just to give me that great feeling when I'm done.



At 08:47 PM 2/18/98 , you wrote:
--    --
--    --At 06:13 AM 2/8/98 -0800, you wrote:
--    -->p.s. if anyone knows how i could display the answer in radical
form any
--    -->way other than matching it with the list of answers, for example
how to
--    -->make it know that 3.605551275 = \/(13) other than saying "if ans =
--    -->3.605551275 : then : disp(\/(13))" please let me know.  this would
be a
--    -->tremendous improvement to the prog.
--    --
--    --Actually you can use trig. identities for known identities to find
unknown
--    --values precisely:
--    --
--    --sin X = Opposite/Hypotenuse
--    --cos X = Adjacent/Hypotenuse
--    --tan X = Opposite/Adjacent
--    --(sin X)^2 + (cos X)^2 = 1
--    --sin (2X) = 2sin Xcos X
--    --cos (2X) = (cos X)^2 - (sin X)^2
--    --cos (2X) = 2(cos X)^2 - 1
--    --cos (2X) = 1 - 2(sin X)^2
--    --sin (A + B) = sin Acos B + cos Asin B
--    --sin (A - B) = sin Acos B - cos Asin B
--    --cos (A + B) = cos Acos B - sin Asin B
--    --cos (A - B) = cos Acos B + sin Asin B
--    --tan (A + B) = (tan A + tan B)/(1 - tan Atan B)
--    --tan (A - B) = (tan A - tan B)/(1 + tan Atan B)
--    --
--    --Using the various identities and knowledge from pre-calc (actually
learned
--    --the stuff in FST (Functions, Statistics, and Trig.)) you can
calculate ANY
--    --angle from known angles by combining various indentities together.
Anyone
--    --up to the challenge of making the ultimate routine to convert any
input
--    --angle into a radical expression?  Everything's here that you
need...just
--    --takes TIME to write it (which we don't have much left of because of
WWIII
--    --starting within the month).
--    --
--    --
--    --                 Thomas J. Hruska -- thruska@tir.com
--    --Shining Light Productions -- "Meeting the needs of fellow programmers"
--    --         http://www.geocities.com/SiliconValley/Heights/8504
--    --                    http://shinelight.home.ml.org
--    -- 

Alex

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http://www.fortunecity.com/skyscraper/coding/190/index.html

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kimo@iland.net


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