Re: Ti-86, ROM 1.3: BUG with function of function!?
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Re: Ti-86, ROM 1.3: BUG with function of function!?
At 11:56 2000-01-02 -0600, Michael Erlewine wrote:
>yes, that is obviously a bug. It switches into the normal roaming cursor
>mode while using the trace cursor. It's not a feature, and It still happens
>on my newer 1.6 ROM 86.
>
>As Ray has said, your function is incorrect, though. y2=y1/x is the correct
>one, and it works flawlessly. The question really now is why y2=y1(x)/x,
>which should be interpreted by the OS as y2=(y1*x)/x, which equals y1. But
>the graph incorrectly displays this as if y2=y1/x.
Pardon? Incorrectly? I may misinterpret you but... Assume this:
y1=x^2+x
y2=y1*(x+1)
y3=y1(x+1)
y4=(x^2+x)*(x+1)
y5=(x+1)^2+(x+1)
Does y2 equal y3? And if so, which of y4 and y5 do they equal?
No, y2 is the same as y4, and y3 equals y5. y2 and y3 is not the same --
e.g. y1(2)=2^2+2=6, y1*2=(x^2+x)*2. Thus y1(x) is essentially the same as
y1, (y1 with every x replaced with x).
-- Johan Winge
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