Re: -2x^2 +500 !!!
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Re: -2x^2 +500 !!!
At 04:04 PM 3/10/1999 -0600, you wrote:
Why bother doing all of that? You can look at the equation and see that
500 is the maximum.
>take the 1st derivitive of the equation:
>-4x, and set that equal to 0, and solve for x:
>-4x=0
>x=0
>set in original equation and solve for f(x):
>f(0)=-2(0)^2+500
>f(0)=-2(0)+500
>f(0)=0+500
>f(0)=500
>so,
>(x,f(x))=(0,500)
>is the maximum of the f(x)=-2x^2+500 equation.
>
>kaus
>
>Perez-Franco <Perez-Franco@mindless.com> wrote in message
>7c426t$26q$1@nnrp1.dejanews.com">news:7c426t$26q$1@nnrp1.dejanews.com...
>>In article <0X9F2.711$RF.3791@news020.image.dk>,
>> "David Winslxw" <dwi@image.dk> wrote:
>>> If I should the find highest (x,y) value in a coordinate system for
>above
>>> function how to you do that on a ti-92. Please advise
>>
>>What do you mean with highest?
>>
>>-----------== Posted via Deja News, The Discussion Network ==----------
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