Re: TI-89 and volume...

To: CALC-TI@LISTS.PPP.TI.COM
Subject: Re: TI-89 and volume...
From: "M.M." <mistermagoo@INAME.COM>
Date: Fri, 16 Apr 1999 04:36:52 GMT
Organization: Bell Solutions
References: <7f5sr9$u53$1@news3.infoave.net>
Reply-To: "M.M." <mistermagoo@INAME.COM>
Xref: paladin.american.edu bit.listserv.calc-ti:28674

If you type hit the intergral key (looks like an S)

then type (sin(x),x,0,2pi) That will give you the area under the curve
sin(x) from 0 to 2pi   (which is 0)

had you typed (sin(x),x,0,pi) the answer would be zero


On Thu, 15 Apr 1999 19:35:16 -0400, "DL_Man" <ummm@no.way> wrote:

>Ok, I recently got a TI-89, and I was wondering if there was a "volume" or
>"area" function for graphs... Say, if I had:  sin(x), with windows set to
>xmin: 0
>xmax: 4
>ymin: 0
>ymax 2(pi)
>
>how could I find the area of everyhing about 0 on the x coordinates?
>Likewise, how could I find the volume of everything above 0 on the x
>coordinates in a 3D graph... I know there is a formula, but is there an
>automated function on the calculator?

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References:

TI-89 and volume...

From: DL_Man <ummm@NO.WAY>