byte->I/O


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byte->I/O



All that hex data form (those compiled numbers) I think they are orginised
into 8 bytes    a line and every 8 numbers makes 1 byte. I think it take up
more memory in the calc since in is not in electronic (I/O) format. Does
anyone know how the calculator converts this low level machine code into an
on/off (I/O) or low high signal and why does it have three pins in the
linkport? I am refering to the TI-83. Thanks.

From: Chris
mecad@scv.net