Re: root problem's


[Prev][Next][Index][Thread]

Re: root problem's



In a message dated 98-01-27 03:24:52 EST, you write:

<<
 Does anybody know why (-x)^(2/3) is not the same as ( 3rd root of (-x)^2) on
 the TI 85 and is the same (but wrong) on the TI 86 ?
 The point is : why can you plott (and solve) root's of (-x) in real ?  I
 thought it is only in comlex numbering system defined ???
  >>
Complex has nothing to do with these.  Cube root of -8 is -2.  Second case,
square of negative is positive, so subsequent cube-root is negative.

The TI prob was not being able to pick up on user's intention, and therefor
interpreting 2/3 as .6666666.......7, which, I guess, gives you your complex
result.

Lomp