Re: Circular definition/TI92


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Re: Circular definition/TI92



Older TI-92s did not incorporate a Circular Definition Error.
Beginning with version 1.4 (about) TI included some code that gave a circular
definition error for what you are trying.

To see the version type F5 then hold down the diamond key and press the left
paren ( key.

I have a version 1.3 that performs the operation you describe, and a version
1.7 that gives the Circular Definition Error.

To get around this, define the function as perhaps
f(u,v)=5+4*u-2*u^2+3v-v^2
then evaluate
f(x,-x)
------------------------------------------------------------------
Ben Sultenfuss <bsultenfuss@sfasu.edu>
Stephen F. Austin State University
Department of Mathematics and Statistics
1936 North Street, PO Box 13040, SFA Station
Nacogdoches, Texas 75962-3040
Voice: Office: 409-468-3805   Home: 409-560-5508
Fax: Office: 409-468-1669   Home: 409-560-0038
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-----Original Message-----
From: Christine Hood <hood@HOPI.DTCC.EDU>
To: GRAPH-TI@LISTS.PPP.TI.COM <GRAPH-TI@LISTS.PPP.TI.COM>
Date: Thursday, April 02, 1998 10:31
Subject: Circular definition/TI92


>Hi, I've been monitoring this list for quite some time now and have found
>some of the discussions very interesting. Now I have ran across a problem
>that has me baffled.
>
>I have entered the following into my 92:
>
>Define f(x,y)=5+4*x-2*x^2+3y-y^2
>f(x,-x)
>
>The answer I received was: -3*x^2 + x + 5
>
>Two other students entered the same information into their 92's and got
>the same answer.
>
>A third student entered the same information into his 92 and got the
>error message "circular definition". Why?
>
>Thanks in advance for any help!


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