Re: ti86 graphing question

To: CALC-TI@LISTS.PPP.TI.COM
Subject: Re: ti86 graphing question
From: Tim Brierley <brierley@erols.com>
Date: Mon, 22 Sep 1997 17:15:39 -0400
Organization: Erol's Internet Services
References: <3425DD7F.7CD1@howling.com>
Reply-To: brierley@erols.com
Xref: paladin.american.edu bit.listserv.calc-ti:16994

I dont think you really want to know how to graph the intersection of
the lines, but you want to find the answer to an exuation where the
value is 2.  The easist way to do this is to substitute 2 into the
equation.  Hope this helps...

Tim Brierley
brierley@erols.com


Russell Spreeman wrote:

> I sure hope you can answer a question for me.
>         I'm a relative "newbie" at graphic calcualtors and have a
> TI86.
> I'm
> taking an algebra course. I've figured out how to graph using the
> GRAPH
> function, selecting y(x), and entering the equation of a line in slope
>
> intercept format (i.e. y=mx+b). By selecting upper shading I can get
> the
> set of all values equal to or greater than the value of the equation.
> I
> have also been able to graph the intersection of two equations. No
> problem.
>         But - how do I graph the intersection of two equations when
> one
> of them
> is simply X=2? This would give me a vertical line through X axis at 2,
>
> and include all values of Y. But there is no way to enter in an
> equation
> into the y(x) editor where y = "all values" and x=2 - is there?
>         How do I do this? How do I graph x=2, y="all values"?
>         Thanks a lot. I'd appreciate if you'd respond via email to
>         wolverine@howling.com
>
>         Russ
>
> --
> Visit my website at:
>         http://members.tripod.com/~spreeman/index.html

References:

ti86 graphing question

From: Russell Spreeman <wolverine@howling.com>