Re: TI-92 programmers
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Re: TI-92 programmers
In article <344EBFFD.FBF1FBAC@erols.com>, brierley@erols.com wrote:
> That isn't a very good example, the maximum area of any shape is the
> "regular" of that shape, meaning closest to a circle, meaning all of the
> sides are the same length. This is not calculus, it is algebra 1! (the
> answer, by the way, is 9X9)
>
I think it does make sense to use calculus.
how do you know all the sides are the same length? are you going to prove
that? here's what I did:
rectangle, so 2x + 2y = 36
y=18 - x
now you need area,
area = xy
area = x(18-x)
define(area,x) = x*(18-x)
d(area,x)=0
solve for x
that is your MIN val for x that gives area 36
you could use vertex idea, -b/2a. don't have a clue how to do that with
geometry alone.
J_Samuels (at) yahoo.com
>
> Bobby Atkinson wrote:
>
> > I am looking for some one to help with programming the TI-92 for
> > calculus
> > word problems.
> > example: (solving maximum and minimum problems) Find the maximum
> > possible
> > area of a rectangle whose perimeter is 36 cm.
> > and some related rates problems.
> > thanks for any help
> > reply to: Bobby Atkinson atkinson1@theonramp.net
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