Re : LF: Math Question, possible ROM error..?
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Re : LF: Math Question, possible ROM error..?
i think the question has no object: the function sqrt( ) is defined from 0 to
+infinite...
it is defined as the inverse function of x^2 on a domain on which x->x^2 is
bijective... (ie: [0,+infinite) )
thus, we have sqrt(0)=0
we know that sqrt is continuous on [0,+infinite) ( because x->x^2 is C1: its
inverse on an interval is C0 )
thus, by the def of the continuity, lim( sqrt(x)), x->0 = 0
well: i think i am right.... but i haven't been doing maths for a month...
and i forget fast... i will look at my lessons later..
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