Re: A86: Re: Calendar Formulas


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Re: A86: Re: Calendar Formulas



YEAH! TIME TO STEAL CODE!! YEAH!!

:-)

malcolmj1@juno.com wrote:

 i think i've got it done.  would someone be willing to help test it.  i've attached it at the end. i tried to use php 4's date() function to test it but there seems to be a difference between the function of the two calls (php's date() and my ti86 routine).  i can't find a way to test it out now. =========start dispdate.asm================#include "ti86asm.inc"

.org _asm_exec_ram

 call _clrLCD
 call _homeup
 ld hl,365*4+1
 call Date

 ld a,(Month)
 call PrintNum

 ld a,(Day)
 call PrintNum

 ld hl,_curRow
 inc (hl)
 inc hl
 ld (hl),$00

 ld a,(Year)
 ld l,a
 ld h,0
 ld a,h
 ld de,1970
 add hl,de
 call _dispAHL

 ret

Date:
 ld de,365   ; Days in a year
 ld b,0    ; Starts with zero being the year offset.  The offset
      ; is based on 1984 being year 0.  Year 1 would be 1985, etc.
YearLoop:
 sub a    ; Reset carry flag anticipating 'sbc hl,de' (Subtraction)
 sbc hl,de
 jr c,YearFound  ; It went under zero
 jr z,YearFound  ; It was zero
 inc b    ; Increase year offset
 call CheckLeapYear ; We want to check if it's a leap year.  If so, subtract
      ; one from the total amount of days left to account for those
      ; infamous Feb 29ths!
 jr YearLoop
YearFound:
 ld a,b    ; - Store away the year we found
 ld (Year),a   ; /
 add hl,de   ; Fix it because it just went under 0...put it back.
 ld ix,MonthDays  ; Start of array of bytes holding number of days per month. It's '-1'
      ; because we will be increasing it before we're using it.
 call LeapYearArray ; Run another check for it being a leap year.  This checks
      ; to see if the current year is a leap year. If so, it will
      ; add 12 to hl to move to the start of another array holding
      ; the number of days per months in a leap year (Feb has 29 days).
 ld b,00    ; Start with the month being 00. The first line in the loop increases
      ; it so that it's on January (01).
MonthTallyLoop:
 inc b    ; Increase month counter
 ld d,00    ; Zero Most Significant Byte (MSB) of 'de'
 ld e,(ix)   ; Get that month's number of days. Now 'de = (ix)'
 inc ix    ; Get it ready for the next time around
 xor a    ; Clear flags (For the upcoming 'sbc hl,de')
 sbc hl,de   ; See how it measures up to our cumulative sum
 jr z,MonthFound  ; - Went under so we must be inside the right month now!
 jr c,MonthFound  ; /
 jr MonthTallyLoop
MonthFound:
 .db 0    ; So I can use the Break feature of VTI
 add hl,de
 ld a,l
 or a
 jr nz,DayCont  ; If the day is zero, move it to one (If a=0 Then a=1)
 inc a
DayCont:
 ld (Day),a
 ld a,b
 ld (Month),a  ; Save away the month found
 ret
 
 

LeapYearArray:   ; Check to see if current year is a leap year
 ld a,(Year)   ; Get the year found
 and %00000011  ; If either bit 0 or 1 are set then it's not divisible by four
 ret nz
 ld bc,MonthDaysLeapYear
 ret

PrintNum:
 ld hl,_curRow
 inc (hl)   ; Increase the row
 inc hl
 ld (hl),$00   ; Zero the column
 ld l,a
 ld h,$00
 ld a,h    ; Zero out 'a' also
 jp _dispAHL

CheckLeapYear:   ; We need to check if it's a leap year. If divisible by
      ; 4 then it probably is. To divide by 4 we're going to
      ; copy it to 'a' and shift it right twice ( a /2 /2 = 4 ). A
      ; binary number is only divisible by 4 if its bits 0 and 1 are
      ; reset (i.e. %XXXXXX00 is divisible by 4 whereas %XXXXXX01 is not).
 ld a,b    ; Get it into 'a' so we can mess with it
 and %00000011
 ret nz    ; If there was a bit in either bit 0 or 1 then it wasn't divisible by four
 dec hl    ; Decrease total number of days left
 ret

Month: .db 0
Day: .db 0
Year: .db 0

MonthDays:
 .db 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
MonthDaysLeapYear:
 .db 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
.end

========================that should be all the source you need.  if anyone wants me to email them the *.asm source, let me know.  i hope this routine really works.  i really appreciate this you guys! > Date: Fri, 2 Feb 2001 12:10:42 -0800
> From: rabidcow@juno.com
> Subject: Re: A86: Calender Formulas thanks. i wrote the above routine and then checked my mail and found what you said.  it's been a while since i've talked to you. jimi malcolm
mailto:malcolmj1@juno.com
http://guide.ticalc.org


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