A86: Re: a pretty fast multiply method...


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A86: Re: a pretty fast multiply method...




Couldn't exactly tell from how you had written it; but you know that (A+B)(A+B)/4 - (A-B)(A-B)/4 is the same as ((A+B)(A+B) - (A-B)(A-B))/4 ... that could save you one division step (haven't seen your code).  It's the power of fractions.  Okay, later.
--Joe

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