Re: A86: Re: mod(op1,op2) == 0


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Re: A86: Re: mod(op1,op2) == 0




Sorry, I guess I need a better Assembly to English translator.  Would you 
like to try that again for me, a little slower this time?

In a message dated 12/1/99 6:51:16 PM Eastern Standard Time, 
kirkmeyer@bigfoot.com writes:

> 
>  There is a call table to ROM page 5, and on it are contained commands that
>  take two arguments, such as GCF, and mod. One of the arguments is in OP1 
and
>  the other is pushed onto the OP stack. Since there's no documentation,
>  you'll just have to keep trying numbers until you find the correct # for
>  mod...
>  
>  ----- Original Message -----
>  From: <Jeanne9005@aol.com>
>  To: <assembly-86@lists.ticalc.org>
>  Sent: Wednesday, December 01, 1999 8:48 AM
>  Subject: A86: mod(op1,op2) == 0
>  
>  
>  >
>  > How do I do mod(op1,op2) == 0?  I have tried many ways, but cannot
>  remember
>  > how it's done.
>  >
>  > Glen
>  > tutorial1.cjb.net
>  >


Glen
tutorial1.cjb.net