Re: A86: Re: Re: Questions


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Re: A86: Re: Re: Questions




>So at the fourth byte of a normal basic prog it would be: 00
>and at the fourth byte of a locked basic prog would be:   0029

Not quite. The third byte of a Basic program (right after size bytes) is
the $00.
But the header bytes of a protected program are $8e29. Thus there is one
more header byte in a prot program, and you mush have this byte.
I am working on a way to inc the size of a program. I just need to get some
info on some rom calls.

>Yes?  No?  So this means I have to move everything down a byte to
>edit-lock a program?  What would happen if I left out the 00 and put >in
29 by itself? Probably would not run, but i am not sure.


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