[A83] Re: TI-OS resumes

To: assembly-83@lists.ticalc.org
Subject: [A83] Re: TI-OS resumes
From: "Dan Weiss" <dwedit@hotmail.com>
Date: Thu, 23 Aug 2001 14:22:39 -0500
Reply-To: assembly-83@lists.ticalc.org

HL isn't used at all in calls and jumps.  But you can pop the return address 
for a call into any register pair, since it uses the stack.


>From: Gavin Olson <gtolson@snet.net>
>Reply-To: assembly-83@lists.ticalc.org
>To: assembly-83@lists.ticalc.org
>Subject: [A83] Re: TI-OS resumes
>Date: Thu, 23 Aug 2001 08:44:37 -0400
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>
>Was it actually hl, or was it just a 16 bit place somewhere?  If it was hl,
>calling could really screw things up (not that you should depend on
>registers around calls and jps :-)
>
>At 07:37 PM 8/22/2001 +0000, you wrote:
>
> >The other day it was mentioned that when a label is called,
> >it stores the ram location of the call xxxx in hl and the pushes
> >it. And ret then pops hl, increments it and then goes there,
> >So I though, when a prgm is executed like call prgm,
> >the only thing I should do is to pop hl and in hl would be
> >where the TI-OS in the ram or rom is working.
> >
> >       SUCKER
> >
> >
> > >Wait, wait, what are you referrring to?
> > >
> > > > About the pop hl in the beginning of a prgm,
> > > > this isn't right. It would be 529Eh (TI-83-).
> > > > I was thinking for a while asm programs were
> > > > executed like call xxxx, but they use _exec_assmebly
> > >AFAIK, _exec_assembly just clears out the ram at the progstar location, 
>and
> > >then calls the program.
> > >
> > >(well, actually I believe it pushes some return address onto the stack,
> > >and then jp's to 9327h, but that's a different story, with the same 
>effect
> > >to
> > >the programmer)
> > >
> > >
> > > > and I don't know how I should get the place in the ram
> > > > where this code will be executed out of a romcall...
> > > >
> > > >       SUCKER
> > > >
> > > > (next time think first???)
> > > >
> > > >
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>


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Follow-Ups:
[A83] Re: TI-OS resumes
From: Peter-Martijn Kuipers <hyper@hysoft-automation.com>