Re: A83: Re: Square root of 0, OT


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Re: A83: Re: Square root of 0, OT




But, 

A * B = C, then C / A = B

0 * 0 = 0, then 0 / 0 = 0

That doesn't work... That is the basis of how they relate to each other

Harper Maddox wrote:
> 
> Im assuming that the calculator decided to use the wrong properties of math.
>                                               __
> since 0*0=0, then wouldnt the \/ 0  be zero too
> 
> because the square root of a number is equal to a number, which when
> multiplied by itself equals the original number inside the square root.
> 
> -Harper Maddox
> 
> jerky@ebicom.net
> IRC nick: Geori
> ICQ: 1214597
> 
> -----Original Message-----
> From: Scott Dial (Revenant) <homosapian@geocities.com>
> To: ASM83 <assembly-83@lists.ticalc.org>
> Date: Friday, September 04, 1998 10:41 PM
> Subject: A83: Square root of 0, OT
> 
> >
> >This is extremely off topic but I figured somebody could tell me here.
> >The square root of 0 according to my handy-dandy TI-83 is 0. But, here
> >is where I am lost. Wouldn't the below equation rule 0 as non-real?
> >
> >   ___        2
> >  / 2   --   X
> >\/ X    --  ---
> >             X
> >
> >If X was zero make this impossible? And if not then how can you prove
> >the square root of 0 is 0.
> >
> >BTW, forgive my ignorance if this something that isn't that complicated.
> >
> >-Revenant
> >

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