A83: Re: Square root of 0, OT
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A83: Re: Square root of 0, OT
Im assuming that the calculator decided to use the wrong properties of math.
__
since 0*0=0, then wouldnt the \/ 0 be zero too
because the square root of a number is equal to a number, which when
multiplied by itself equals the original number inside the square root.
-Harper Maddox
jerky@ebicom.net
IRC nick: Geori
ICQ: 1214597
-----Original Message-----
From: Scott Dial (Revenant) <homosapian@geocities.com>
To: ASM83 <assembly-83@lists.ticalc.org>
Date: Friday, September 04, 1998 10:41 PM
Subject: A83: Square root of 0, OT
>
>This is extremely off topic but I figured somebody could tell me here.
>The square root of 0 according to my handy-dandy TI-83 is 0. But, here
>is where I am lost. Wouldn't the below equation rule 0 as non-real?
>
> ___ 2
> / 2 -- X
>\/ X -- ---
> X
>
>If X was zero make this impossible? And if not then how can you prove
>the square root of 0 is 0.
>
>BTW, forgive my ignorance if this something that isn't that complicated.
>
>-Revenant
>
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