Re: A83: Tutorials...


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Re: A83: Tutorials...




Trey Jazz wrote:

> >> PPS:  I failed my math final :)...there was a question on "mutual
> >> exclusive"...if you have the number 341521 how many ways can you make a
> odd
> >> number if you re-arrange numbers.  360...please say 360 :)...
> >
> >There are 3 different odd numbers in that 6 digit number, so there are 3
> >possibilites for the last place value.  The other place values don't
> matter.
> >So there are 5 posibilites for the first place value, 4 for the second, 3
> for
> >the third, 2 for the fouth, 1 for the fith, and 3 for the last one.
> >5*4*3*2*1*3 = 360.  But since there are two 1's, you must divide that by 2
> >because you could swap the 1's and you would get the same number.  So I
> think
> >the answer should be 180.
>
> the sample space would still have those two 1s in there so i think it should
> be 360

No, because the two 1's are identical, you can't tell the difference between
them.  11 is the same as 11.  So you have to divide by 2 so you don't count them
twice.

--
Bryan Rabeler <brabeler@ticalc.org>
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